Matematika
Test _Amaliy matematika 2
muallif: gnyva7 · 229 ta savol ·
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QuizPilotda o'ynash
#1
Funksiya hosilasini toping: 𝑓(𝑥) = 4𝑒2.
- 8
- 0
- 4e
- 8x
Javobni ko'rish
0
#2
Agar f(x) = 8 bo’lsa, quyidagini toping: f′(x) =?
- 2
- 8
- 1
- 0
Javobni ko'rish
0
#3
Funksiya hosilasini toping: 𝑓(𝑥) = 4𝑥2 −2
- 0
- 8x
- 4x−2
- 8
Javobni ko'rish
8x
#4
Agar 𝑓(𝑥) = 4𝑥3 −2𝑥+ 1 bo’lsa, quyidagini toping: f′(1) =?
- 14
- 10
- 12x−2
- 3
Javobni ko'rish
10
#5
Agar 𝑓(𝑥) = 𝑥3 + 2𝑥 bo’lsa, quyidagini toping: f′(1) =?
- 0
- 3𝑥2 + 2𝑥
- 5
- 3
Javobni ko'rish
5
#6
Agar f(x) = sin x+ 4 bo’lsa, quyidagini toping: f′(x) =?
- 4
- cosx
- 0
- sinx
Javobni ko'rish
cosx
#7
Agar f(x) = sin x−cosx bo’lsa, quyidagini toping: f′(x) =?
- 2 sinx
- cosx+ sin x
- 2 cosx
- 0
Javobni ko'rish
cosx+ sin x
#8
Agar f(x) = 4·cosx bo’lsa, quyidagini toping: f′(π/4) =?
- 0
- 1
- −2√2
- −4 sinx
Javobni ko'rish
−2√2
#9
Agar f(x) =−sinx+ 7 bo’lsa, quyidagini toping: f′(π/3) =?
- 0
- −√3/2
- √2/2
- −1/2
Javobni ko'rish
−1/2
#10
Agar f(x) = cos x−2x bo’lsa, quyidagini toping: f′(π/6) =?
- 0
- √3/2−π/3
- −5/2
- √3/2
Javobni ko'rish
−5/2
#11
Funksiya hosilasini toping: f(x) = 5x.
- 5𝑥𝑙𝑛5
- 1
- 5𝑥
- 5𝑥
Javobni ko'rish
5𝑥𝑙𝑛5
#12
Funksiya hosilasini toping: 𝑓(𝑥) = 𝑒𝑥.
- 𝑒𝑥
- 1
- 𝑒𝑥
- 0
Javobni ko'rish
𝑒𝑥
#13
Agar 𝑓(𝑥) = 𝑥3 + 3𝑥 bo’lsa, quyidagini toping: f′(x) =?
- 3𝑥
- 32 + 3𝑥
- 3𝑥2 + 3𝑥𝑙𝑛3
- 3𝑥
Javobni ko'rish
3𝑥2 + 3𝑥𝑙𝑛3
#14
Agar 𝑓(𝑥) = 𝑒𝑥+ 3𝑥2 + 7𝑥 bo’lsa, quyidagini toping: f′(0) =?
- 𝑒𝑥+ 6𝑥+ 7
- 1
- 0
- 8
Javobni ko'rish
8
#15
Agar 𝑓(𝑥) = 7𝑥 bo’lsa, quyidagini toping: f′(0) =?
- 7𝑥𝑙𝑛7
- 0
- ln7
- 7𝑥
Javobni ko'rish
ln7
#16
Agar 𝑓(𝑥) = 3𝑥 bo’lsa, quyidagini toping: f′(1) =?
- 1
- 3ln3
- 0
- ln3
Javobni ko'rish
3ln3
#17
Agar 𝑓(𝑥) = 3𝑥2 + sin30𝑜 bo’lsa, quyidagini toping: f′(1) =?
- 7
- 0
- 5
- 6
Javobni ko'rish
6
#18
Agar 𝑓(𝑥) = 2𝑥4 + 3𝑥2 bo’lsa, quyidagini toping: f′(x) =?
- 8𝑥3 + 6𝑥
- 8𝑥3 −6𝑥
- 14𝑥
- 8𝑥4 + 6𝑥3
Javobni ko'rish
8𝑥3 + 6𝑥
#19
Agar 𝑓(𝑥) = 2𝑥3 + 3𝑥−7 bo’lsa, quyidagini toping: f′(x) =?
- 2𝑥2 −4𝑥
- 2𝑥+ 4
- 6𝑥2 + 3
- 6𝑥+ 5
Javobni ko'rish
6𝑥2 + 3
#20
Agar 𝑓(𝑥) = 𝑥−8 bo’lsa, quyidagini toping: f′(x) =?
- 𝑓′(𝑥) = −8𝑥
- 𝑓′(𝑥) = −8𝑥−7
- 𝑓′(𝑥) = 8𝑥7
- 𝑓′(𝑥) = −8𝑥−9
Javobni ko'rish
𝑓′(𝑥) = −8𝑥−9
#21
Agar 𝑓(𝑥) = 𝑥−3 + 𝑥−2 bo’lsa, quyidagini toping: f′(x) =?
- 𝑓′(𝑥) = −3𝑥−4 −2𝑥−3
- 𝑓′(𝑥) = 𝑥−4 −𝑥−3
- 𝑓′(𝑥) = −3𝑥−2 + 2𝑥−1
- 𝑓′(𝑥) = 𝑥−2 −𝑥−1
Javobni ko'rish
𝑓′(𝑥) = −3𝑥−4 −2𝑥−3
#22
Agar f(x) = 2 sin x·cosx bo’lsa, quyidagini toping: f′(π/2) =?
- 2
- 0
- 1
- 1
Javobni ko'rish
2
#23
Agar 𝑓(𝑥) = 2𝑥2 + 1 bo’lsa, quyidagini toping: f′(π/4) =?
- π
- π/2
- 1
- 0
Javobni ko'rish
π
#24
Agar (𝑥) = cos (𝑥2) bo’lsa, quyidagini toping: f′(x) =?
- sin (𝑥2) ∗(2𝑥)
- −sin (𝑥2) ∗(2𝑥)
- cos (𝑥2) ∗(2𝑥)
- 2 ∗sin (𝑥2)
Javobni ko'rish
−sin (𝑥2) ∗(2𝑥)
#25
Agar 𝑓(𝑥) = 𝑐𝑜𝑠2(5𝑥)bo’lsa, quyidagini toping:f′(x) =?
- sin(5x)
- −5·sin(10 x)
- 5·sin(10 x)
- −5·sin(5x)
Javobni ko'rish
−5·sin(10 x)
#26
Agar f(x) = 5 sin x+ 3 cos x bo’lsa, quyidagini toping: f′(π/4) =?
- 4√2
- −√2
- √2
- −2√3
Javobni ko'rish
√2
#27
Agar 𝑓(𝑥) = 1 3 𝑥3 −16𝑥 bo’lsa, quyidagini toping: f′(4) =? .
- 2
- 3
- 0
- 1
Javobni ko'rish
0
#28
Agar 𝑓(𝑥) = 3𝑥∗2𝑥 bo’lsa, quyidagini toping: f′(0) =?
- 3ln 2
- 3
- 3
- 0
Javobni ko'rish
3
#29
Agar 𝑓(𝑥) = 2𝑥∗3𝑥 bo’lsa, quyidagini toping:f′(0) =?
- 2
- 0
- 2
- 2ln 3
Javobni ko'rish
2
#30
Funksiya hosilasini toping: 𝑦= 𝑒𝑥∗𝑥2.
- 𝑒𝑥(𝑥2 + 𝑥)
- 𝑒𝑥(𝑥2 + 2𝑥)
- 𝑒𝑥(𝑥2 + 2)
- 𝑒𝑥(2𝑥+ 1)
Javobni ko'rish
𝑒𝑥(𝑥2 + 2𝑥)
#31
Funksiya hosilasini toping: 𝑦= 𝑒𝑐𝑡𝑔𝑥.
- −
- 𝑒𝑐𝑡𝑔𝑥𝑙𝑛𝑥
- 𝑒𝑐𝑡𝑔𝑥
- 𝑐𝑡𝑔𝑥∗𝑒𝑐𝑡𝑔𝑥−1
Javobni ko'rish
−
#32
Agar f(x) = ln(sin x) bo’lsa, quyidagini toping: f′(π/4) =?
- 1
- 3
- 1
- −√3
Javobni ko'rish
1
#33
Funksiya hosilasini toping: y= sin(cos x).
- cosx·sin(cos x)
- −sinx·cos(cos x)
- −cosx·sin(cos x)
- sinx·cos(cos x)
Javobni ko'rish
−sinx·cos(cos x)
#34
Ushbu y = 3x² − 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = 3x³ − x + C
- F(x) = 3x³ − 2x + C
- F(x) = ⅓x³ − x + C
- F(x) = x³ − x + C
Javobni ko'rish
F(x) = x³ − x + C
#35
Ushbu y = x − 3 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x² − x + C
- F(x) = ½x² − 3x + C
- F(x) = ⅓x² − 3x + C
- F(x) = ⅓x² − 3x + C
Javobni ko'rish
F(x) = ½x² − 3x + C
#36
Ushbu y = x − 2 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ½x² − 2x + C
- F(x) = ½x² − x + C
- F(x) = ½x² − ½x + C
- F(x) = ½x³ − 3x + C
Javobni ko'rish
F(x) = ½x² − 2x + C
#37
Ushbu y = 2x − 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = 2x² − x + C
- F(x) = x² − x + C
- F(x) = ½x² − x + C
- F(x) = ⅓x² − 3x + C
Javobni ko'rish
F(x) = x² − x + C
#38
Ushbu y = x² − 2x funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x³ − 2x² + C
- F(x) = ⅓x² − ½x² + C
- F(x) = ⅓x³ − x² + C
- F(x) = ⅓x³ − x + C
Javobni ko'rish
F(x) = ⅓x³ − x² + C
#39
Ushbu y = 2x² − 2x + 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅔x³ − 2x² + 1 + C
- F(x) = ⅔x² − 2x + 1 + C
- F(x) = ⅔x³ − x² + x + C
- F(x) = ⅓x³ − x² + x + C
Javobni ko'rish
F(x) = ⅔x³ − x² + x + C
#40
Ushbu y = 2x − 2 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = 2x² − 3x + C
- F(x) = x² − 2x + C
- F(x) = ½x² − 2x + C
- F(x) = 2x² − 2x + C
Javobni ko'rish
F(x) = x² − 2x + C
#41
Ushbu y = x² − x + 2 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x³ − x + C
- F(x) = ⅓x³ − 2x² + C
- F(x) = ⅓x³ − ½x² + 2x + C
- F(x) = ⅓x³ − ½x² + 2x + C
Javobni ko'rish
F(x) = ⅓x³ − ½x² + 2x + C
#42
Ushbu y = 4x³ − 4x funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ¼x² − 4x + C
- F(x) = ¼x⁴ − 4x + 4C
- F(x) = ½x⁴ − 4x + 4C
- F(x) = x⁴ − 2x² + C
Javobni ko'rish
F(x) = x⁴ − 2x² + C
#43
Ushbu y = x² − 4 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x³ − 4x + C
- F(x) = ¼x⁴ − 4x + C
- F(x) = ¼x³ − 4x² − 4C
- F(x) = ⅓x³ − 4x + 4 + C
Javobni ko'rish
F(x) = ⅓x³ − 4x + C
#44
Ushbu y = x² − 2x + 3 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x³ − ½x² + 3x + 3 + C
- F(x) = ½x² − 2x + 3 + C
- F(x) = ½x³ − x² + 3 + C
- F(x) = ⅓x³ − x² + 3x + C
Javobni ko'rish
F(x) = ⅓x³ − x² + 3x + C
#45
Ushbu y = x² − 4 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x³ − 4x + C
- F(x) = ⅓x³ − 4x + 4 + C
- F(x) = ¼x³ − 4x + C
- F(x) = ⅓x³ − 3x + C
Javobni ko'rish
F(x) = ⅓x³ − 4x + C
#46
Ushbu y = 1⁄x − 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ½ ln² x − x + C
- F(x) = 2 ln x − x + 1 + C
- F(x) = ln x² − x + C
- F(x) = ln x − x + C
Javobni ko'rish
F(x) = ln x − x + C
#47
Ushbu y = x² − x + 2 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ½x² − ½x + 2 + C
- F(x) = ½x² − ½x + 4 + C
- F(x) = ¼x⁴ − ⅓x³ + 2x² + 2x + C
- F(x) = ⅓x³ − ½x² + 2x + C
Javobni ko'rish
F(x) = ⅓x³ − ½x² + 2x + C
#48
Ushbu y = ½x² − x + 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅙x³ − ½x² + 2x + 1 + C
- F(x) = ⅙x³ − x² + 1 + C
- F(x) = ⅙x³ − ½x² + x + C
- F(x) = ⅙x² − x + C
Javobni ko'rish
F(x) = ⅙x³ − ½x² + x + C
#49
Ushbu y = 1⁄(x − 1) + x² + 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ln(x − 1) + ⅓x³ + x + C
- F(x) = ln(x − 1) + ½x² + x + C
- F(x) = ln(x − 1) + ½x⁴ + 2x + C
- F(x) = ln(x − 1) + ⅙x³ + x + C
Javobni ko'rish
F(x) = ln(x − 1) + ⅓x³ + x + C
#50
Ushbu y = x − 1⁄x + 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ½x² − ln x + x + C
- F(x) = ⅙x³ − 2 ln x + x + C
- F(x) = ¼x² − 2 ln x + x + C
- F(x) = ⅙x³ − ln x + x + C
Javobni ko'rish
F(x) = ½x² − ln x + x + C
#51
Ushbu y = 3x² + 2x − 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = x³ + x² − x + C
- F(x) = ⅓x³ + x² − x + C
- F(x) = x³ + 2x² − x + C
- F(x) = 3x³ + x² − x + C
Javobni ko'rish
F(x) = x³ + x² − x + C
#52
Ushbu y = 4x − 5 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = x² − 5x + C
- F(x) = 4x² − 5x + C
- F(x) = 2x² − 10x + C
- F(x) = 2x² − 5x + C
Javobni ko'rish
F(x) = 2x² − 5x + C
#53
Ushbu y = x² + 2x funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x³ + 3x + C
- F(x) = ½x² + 3x + C
- F(x) = ⅓x³ + x² + C
- F(x) = x³ + 3x² + C
Javobni ko'rish
F(x) = ⅓x³ + x² + C
#54
Ushbu y = 2x³ funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅔x⁴ + C
- F(x) = ½x⁴ + C
- F(x) = 2x⁴ + C
- F(x) = x⁴ + C
Javobni ko'rish
F(x) = ½x⁴ + C
#55
Ushbu y = x² − 3x + 1 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅓x³ − 3x² + x + C
- F(x) = ⅓x³ − 3⁄2x² + x + C
- F(x) = x³ − 3x² + x + C
- F(x) = ½x² − 3x + 1 + C
Javobni ko'rish
F(x) = ⅓x³ − 3⁄2x² + x + C
#56
Ushbu y = 6x² funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = 6x³ + C
- F(x) = 3x³ + C
- F(x) = 2x³ + C
- F(x) = x³ + C
Javobni ko'rish
F(x) = 2x³ + C
#57
Ushbu y = 5 funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = x⁵ + C
- F(x) = ½x² + C
- F(x) = 5x + C
- F(x) = 5 + C
Javobni ko'rish
F(x) = 5x + C
#58
Ushbu y = 7x funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = 7x + C
- F(x) = 7x² + C
- F(x) = ½x² + C
- F(x) = 7⁄2x² + C
Javobni ko'rish
F(x) = 7⁄2x² + C
#59
Ushbu y = x³ − x funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ¼x⁴ − ½x² + C
- F(x) = x⁴ − x² + C
- F(x) = ½x⁴ − ½x² + C
- F(x) = ¼x³ − ½x² + C
Javobni ko'rish
F(x) = ¼x⁴ − ½x² + C
#60
Ushbu y = 2x² − 4x funksiyaning boshlang‘ich funksiyalaridan birini toping.
- F(x) = ⅔x² − 2x + C
- F(x) = x³ − 4x² + C
- F(x) = ⅔x³ − 2x² + C
- F(x) = x³ − 2x² + C
Javobni ko'rish
F(x) = ⅔x³ − 2x² + C
#61
Ushbu ∫𝑑𝑥 integralni hisoblang.
- 𝑥+ 𝐶
- 𝐶
- −𝑥+ 𝐶
- 𝑥−𝐶
Javobni ko'rish
𝑥+ 𝐶
#62
Ushbu −∫𝑑𝑥 integralni hisoblang.
- 𝑥−𝐶
- 𝐶
- 𝑥+ 𝐶
- −𝑥+ 𝐶
Javobni ko'rish
−𝑥+ 𝐶
#63
Ushbu ∫2𝑥𝑑𝑥 integralni hisoblang.
- −
- 2𝑥
- 2𝑥
- 2𝑥
Javobni ko'rish
2𝑥
#64
Ushbu ∫ 2𝑑𝑥 integralni hisoblang.
- 2𝑥+ 𝐶
- 𝑥−𝐶
- −𝑥+ 𝐶
- 𝐶
Javobni ko'rish
2𝑥+ 𝐶
#65
Ushbu −∫ 2𝑑𝑥 integralni hisoblang.
- 𝑥−𝐶
- 𝑥+ 𝐶
- 𝐶
- −2𝑥+ 𝐶
Javobni ko'rish
−2𝑥+ 𝐶
#66
Ushbu ∫ 2𝑥𝑑𝑥 integralni hisoblang.
- 2𝑥
- −
- 2𝑥
- 2𝑥
Javobni ko'rish
2𝑥
#67
Ushbu ∫ 𝑒3𝑥+1𝑑𝑥 integralni hisoblang.
- 𝑒3𝑥+1
- 𝑒3𝑥+1
- 𝑒3𝑥+1
- 𝑒3𝑥+1
Javobni ko'rish
𝑒3𝑥+1
#68
Ushbu ∫ 2024𝑥2023𝑑𝑥 integralni hisoblang.
- 𝑥2024
- 𝑥2024 + 𝐶
- 𝑥2023
- −
Javobni ko'rish
𝑥2024 + 𝐶
#69
Ushbu ∫ 4𝑑𝑥 integralni hisoblang.
- x
- 𝑥2
- 𝑥
- 4𝑥+ 𝐶
Javobni ko'rish
4𝑥+ 𝐶
#70
Ushbu ∫ (sin 𝑥+ cos 𝑥)𝑑𝑥 integralni hisoblang.
- −sin 𝑥+ cos 𝑥+ 𝐶
- sin 𝑥+ cos 𝑥+ 𝐶
- −sin 𝑥−cos 𝑥+ 𝐶
- sin 𝑥−cos 𝑥+ 𝐶
Javobni ko'rish
−sin 𝑥+ cos 𝑥+ 𝐶
#71
Ushbu ∫ sin2 𝑥𝑑𝑥+ ∫ cos2 𝑥𝑑𝑥 integralni hisoblang.
- 𝑥+ 𝐶
- sin 𝑥+ cos 𝑥+ 𝐶
- sin2 𝑥−cos2 𝑥+ 𝐶
- sin2 𝑥+ cos2 𝑥+ 𝐶
Javobni ko'rish
𝑥+ 𝐶
#72
Ushbu ∫ 1−sin2 𝑥 cos 𝑥𝑑𝑥 integralni hisoblang.
- sin 𝑥+ cos 𝑥+ 𝐶
- sin 𝑥+ B
- cos 𝑥+ 𝐶
- sin 𝑥−cos 𝑥+ 𝐶
Javobni ko'rish
cos 𝑥+ 𝐶
#73
Ushbu ∫ 1−cos2 𝑥 sin 𝑥 𝑑𝑥 integralni hisoblang.
- sin 𝑥+ 𝐶
- −cos 𝑥+ 𝐶
- cos 𝑥+ 𝐶
- −sin 𝑥+ 𝐶
Javobni ko'rish
sin 𝑥+ 𝐶
#74
Ushbu ∫ (1 + 𝑡𝑔2𝑥)cos2 𝑥𝑑𝑥 integralni hisoblang.
- −𝑥+ 𝐶
- 𝑥+ 𝐶
- cos2 𝑥+ 𝐶
- tg𝑥+ 𝐶
Javobni ko'rish
𝑥+ 𝐶
#75
Ushbu ∫ (tg𝑥⋅ctg𝑥)𝑑𝑥 integralni hisoblang.
- 𝑥+ 𝐶
- −𝑥+ 𝐶
- tg𝑥+ 𝐶
- ctg𝑥+ 𝐶
Javobni ko'rish
𝑥+ 𝐶
#76
Ushbu ∫ ( 5 2 sin 𝑥+ 4) 𝑑𝑥 integralni hisoblang.
- −
- 5
- −
- −
Javobni ko'rish
−
#77
Ushbu ∫ (−2sin 𝑥+ 3cos 𝑥)𝑑𝑥 integralni hisoblang.
- −2cos 𝑥+ 3sin 𝑥+ 𝐶
- 2cos 𝑥+ 3sin 𝑥+ 𝐶
- −2cos 𝑥−3sin 𝑥+ 𝐶
- 2cos 𝑥−3sin 𝑥+ 𝐶
Javobni ko'rish
2cos 𝑥+ 3sin 𝑥+ 𝐶
#78
Ushbu ∫ (4𝑥+ 4)𝑑𝑥 integralni hisoblang.
- 4𝑥
- 4𝑥
- 4𝑥
- 4𝑥
Javobni ko'rish
4𝑥
#79
Ushbu ∫ (𝑒+ 𝑒𝑥)𝑑𝑥 integralni hisoblang.
- 𝑒𝑥+ 𝐶
- 𝑒𝑥+ 𝑒𝑥+ 𝐶
- 𝑒𝑥−𝑒𝑥+ 𝐶
- 𝑒𝑥+ 𝐶
Javobni ko'rish
𝑒𝑥+ 𝑒𝑥+ 𝐶
#80
Ushbu ∫ (𝑒𝑥+4 + 1 𝑥) 𝑑𝑥 integralni hisoblang.
- 𝑒𝑥+4 + ln 𝑥+ 𝐶
- 3𝑥+ 𝑒3𝑥+ 𝐶
- ln 3𝑥+ 𝑒3𝑥+ 𝐶
- ln 𝑥+ 𝑒𝑥+ 𝐶
Javobni ko'rish
𝑒𝑥+4 + ln 𝑥+ 𝐶
#81
Ushbu ∫ 𝑒𝑥+𝑦𝑑𝑥 integralni hisoblang.
- 𝑒𝑦+ 𝐶
- 𝑒𝑥+𝑦+ 𝐶
- −𝑒𝑦+ 𝐶
- −𝑒𝑥+ 𝐶
Javobni ko'rish
𝑒𝑥+𝑦+ 𝐶
#82
Ushbu ∫ 𝑒𝑥+𝑦𝑑𝑦 integralni hisoblang.
- 𝑒𝑥+𝑦+ 𝐶
- 𝑒𝑥+ 𝐶
- −𝑒𝑥+𝑦+ 𝐶
- −𝑒𝑦+ 𝐶
Javobni ko'rish
𝑒𝑥+𝑦+ 𝐶
#83
Ushbu ∫ 6𝑥ln 6𝑑𝑥 integralni hisoblang.
- ln 6𝑥+ 𝐶
- 6𝑥+ 𝐶
- −6𝑥+ 𝐶
- 6𝑥+ 𝐶
Javobni ko'rish
6𝑥+ 𝐶
#84
Ushbu ∫ 16𝑥⋅ln 2𝑑𝑥 integralni hisoblang.
- 24𝑥ln 4 + 𝐶
- 24𝑥−4 + 𝐶
- ln 2𝑥+ 𝐶
- 24𝑥+ 𝐶
Javobni ko'rish
24𝑥+ 𝐶
#85
Ushbu ∫ ln3 𝑥 𝑥𝑑𝑥 integralni hisoblang.
- ln5 𝑥
- ln4 𝑥
- ln2 𝑥
- ln3 𝑥
Javobni ko'rish
ln4 𝑥
#86
Ushbu ∫ 2sin 𝑥⋅cos 𝑥𝑑𝑥 integralni hisoblang.
- cos 2𝑥+ 𝐶
- cos2 𝑥+ 𝐶
- sin2 𝑥+ 𝐶
- sin 2𝑥+ 𝐶
Javobni ko'rish
sin2 𝑥+ 𝐶
#87
Ushbu ∫ cos 𝑥 sin 𝑥𝑑𝑥 integralni hisoblang.
- ln |cos 𝑥| + 𝐶
- −ln |sin 𝑥|𝑥+ 𝐶
- −ln |cos 𝑥| + 𝐶
- ln |sin 𝑥| + 𝐶
Javobni ko'rish
ln |sin 𝑥| + 𝐶
#88
Ushbu ∫ 𝑑𝑥 𝑥⋅ln 𝑥𝑑𝑥 integralni hisoblang.
- ln (ln 𝑥) + 𝐶
- −ln (ln 𝑥) + 𝐶
- −ln 𝑥+ 𝐶
Javobni ko'rish
ln (ln 𝑥) + 𝐶
#89
Aniq integralni hisoblang. ∫1 3 𝑥𝑑𝑥
- 2
- 0
- 1
- 4
Javobni ko'rish
4
#90
Aniq integralni hisoblang. ∫1 3 2𝑥𝑑𝑥
- 0
- 4
- 6
- 8
Javobni ko'rish
8
#91
Aniq integralni hisoblang. ∫1 3 3𝑥2𝑑𝑥
- 6
- 26
- 24
- 20
Javobni ko'rish
26
#92
Aniq integralni hisoblang. ∫0 1 4𝑥3𝑑𝑥
- 6
- 1
- 2
- 0
Javobni ko'rish
1
#93
Aniq integralni hisoblang. ∫0 1 3𝑥2𝑑𝑥
- 0
- 1
- 2
- 6
Javobni ko'rish
1
#94
Aniq integralni hisoblang. ∫−1 1 𝑥𝑑𝑥
- 2
- 6
- 1
- 0
Javobni ko'rish
0
#95
Aniq integralni hisoblang. ∫−1 1 𝑥3𝑑𝑥
- 0
- 2
- 1
- 6
Javobni ko'rish
0
#96
Aniq integralni hisoblang. ∫−1 1 𝑥5𝑑𝑥
- 2
- 6
- 1
- 0
Javobni ko'rish
0
#97
Aniq integralni hisoblang. ∫0 2 6𝑥2𝑑𝑥
- 20
- 16
- 10
- 6
Javobni ko'rish
20
#98
Aniq integralni hisoblang. ∫𝜋 6 𝜋 3 cos 𝑥𝑑𝑥
- 1
- 1
- √3−1
- 0
Javobni ko'rish
√3−1
#99
Aniq integralni hisoblang. ∫𝜋 6 𝜋 3 2cos 𝑥𝑑𝑥
- 1
- 1
- √3 −1
- 0
Javobni ko'rish
√3 −1
#100
Aniq integralni hisoblang. ∫0 𝜋 2 sin 𝑥𝑑𝑥
- 1
- 0
- 1
- 1
Javobni ko'rish
1
#101
Aniq integralni hisoblang. ∫1 𝑒4 1 𝑥𝑑𝑥
- 0
- 1
- 4
- 1
Javobni ko'rish
4
#102
∫0 ln 7 𝑒𝑥𝑑𝑥= ?
- 1
- 0
- 6
- 7
Javobni ko'rish
6
#103
Aniq integralni hisoblang. ∫0 1 1 1+𝑥2 𝑑𝑥
- 0
- 𝜋
- 𝜋
- 𝜋
Javobni ko'rish
𝜋
#104
Aniq integralni hisoblang. ∫2 3 𝑥2𝑑𝑥
- 19
- 2
- 1
- 1
Javobni ko'rish
19
#105
Aniq integralni hisoblang. ∫−1 0 𝑒𝑥𝑑𝑥
- 𝑒
- 𝑒−1
- 1
- 1
Javobni ko'rish
𝑒−1
#106
Aniq integralni hisoblang. ∫2 6 2 𝑥𝑑𝑥
- 1
- 0
- 𝑒
- ln 9
Javobni ko'rish
ln 9
#107
Aniq integralni hisoblang. ∫−1 1 𝑥7𝑑𝑥
- 2
- 0
- 6
- 1
Javobni ko'rish
0
#108
Aniq integralni hisoblang. ∫−𝜋 2 𝜋 2 cos 𝑥𝑑𝑥
- 2
- 1
- 1
- 0
Javobni ko'rish
2
#109
Aniq integralni hisoblang. ∫−3 3 𝑥2𝑑𝑥
- 18
- 1
- 11
- 0
Javobni ko'rish
18
#110
Aniq integralni hisoblang. ∫−2 2 𝑥2𝑑𝑥
- 16
- 2
- 1
- 1
Javobni ko'rish
16
#111
Sonli qator qaysi javobda to'g'ri berilgan?
- 𝑎1 + 𝑎2 + 𝑎3 + ⋯+ 𝑎𝑛+ ⋯
- 𝑎1 + 𝑎2 + 𝑎3
- 𝑎1 + 𝑎2 + 𝑎3 + ⋯+ 𝑎𝑛
- 𝑎1
Javobni ko'rish
𝑎1 + 𝑎2 + 𝑎3 + ⋯+ 𝑎𝑛+ ⋯
#112
1 + 1 2 + 1 4 + 1 8 + ⋯ ni hisoblang.
- 1
- 3
- 2
- 1
Javobni ko'rish
2
#113
∑𝑛=1 ∞ (−1)𝑛 2𝑛+1 sonli qatorning yettinchi hadini hisoblang.
- −
- −
- 1
- 1
Javobni ko'rish
−
#114
∑𝑛=1 ∞ 1 √𝑛 sonli qator yaqinlashuvchimi?
- ham yaqinlashuvchi, ham uzoqlashuvchi
- ha, yaqinlashuvchi
- to'g'ri javob berilmagan
- yo'q, uzoqlashuvchi
Javobni ko'rish
yo'q, uzoqlashuvchi
#115
1 + 2 + 3 + ⋯+ 𝑛+ ⋯ sonli qatorning dastlabki 𝑛 ta hadi yig'indisini hisoblang.
- 𝑛
- (𝑛+1)(𝑛+2)
- 𝑛(𝑛+1)
- 𝑛
Javobni ko'rish
𝑛(𝑛+1)
#116
∑𝑛=1 ∞ (−1)𝑛+1 sonli qatorning dastlabki 9 ta hadi yig'indisini hisoblang.
- 1
- 1
- 2
- 0
Javobni ko'rish
1
#117
∑𝑛=1 ∞ (−1)𝑛+1 sonli qatorning dastlabki 12 ta hadi yig'indisini hisoblang.
- 2
- 1
- 0
- 1
Javobni ko'rish
0
#118
∑𝑛=1 ∞ (−1)𝑛+1 sonli qatorning dastlabki 13 ta hadi yig'indisini hisoblang.
- 1
- 1
- 2
- 0
Javobni ko'rish
1
#119
∑𝑛=1 ∞ (−1)𝑛+1 sonli qatorning dastlabki 11 ta hadi yig'indisini hisoblang.
- 1
- 1
- 2
- 0
Javobni ko'rish
1
#120
1 + 1 3 + 1 9 + 1 27 + ⋯+ 1 3𝑛+ ⋯ ni hisoblang.
- 1
- 2
- 1
- 3
Javobni ko'rish
3
#121
∑𝑛=1 ∞ 1 𝑛(𝑛+1) sonli qatorning yig'indisini toping.
- 1
- 1
- 0
- 2
Javobni ko'rish
1
#122
∑𝑛=1 ∞ 2 𝑛(𝑛+1) sonli qatorning yig'indisini toping.
- 1
- 1
- 2
- 0
Javobni ko'rish
2
#123
∑𝑛=1 ∞ 1 𝑛(𝑛+1) sonli qatorning 𝑛 ta yig'indisini toping.
- 𝑛
- 𝑛
- 2−𝑛
- 2𝑛
Javobni ko'rish
𝑛
#124
∑𝑛=1 ∞ 2 𝑛(𝑛+1) sonli qatorning 𝑛 ta yig'indisini toping.
- 2𝑛
- 𝑛
- 2−𝑛
- 𝑛
Javobni ko'rish
2𝑛
#125
1 1⋅3 + 1 2⋅5 + 1 3⋅7 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛=
- 𝑎𝑛=
- 𝑎𝑛=
- 𝑎𝑛= 𝑛
Javobni ko'rish
𝑎𝑛=
#126
1 + 1 4 + 1 16 + 1 64 + ⋯ ni hisoblang.
- 1
- 4
- 1
- 1
Javobni ko'rish
4
#127
∑𝑛=1 ∞ (−1)𝑛 2𝑛+1 sonli qatorning beshinchi hadini hisoblang.
- 1
- −
- 1
- −
Javobni ko'rish
−
#128
∑𝑛=1 ∞ (−1)𝑛 2𝑛+1 sonli qatorning uchinchi hadini hisoblang.
- −
- 1
- −
- 1
Javobni ko'rish
−
#129
∑𝑛=1 ∞ 1 𝑛 sonli qator yaqinlashuvchimi?
- ham yaqinlashuvchi, ham uzoqlashuvchi
- yo'q, uzoqlashuvchi
- to'g'ri javob berilmagan
- ha, yaqinlashuvchi
Javobni ko'rish
yo'q, uzoqlashuvchi
#130
2 + 4 + 6 + ⋯+ 2𝑛+ ⋯ sonli qatorning dastlabki 𝑛 ta hadi yig'indisini hisoblang.
- 𝑛(𝑛+ 1)
- 𝑛
- 𝑛
- (𝑛+1)(𝑛+2)
Javobni ko'rish
𝑛(𝑛+ 1)
#131
∑𝑛=1 ∞ (−1)𝑛 sonli qatorning dastlabki 8 ta hadi yig'indisini hisoblang.
- 0
- 1
- 1
- 2
Javobni ko'rish
0
#132
∑𝑛=1 ∞ (−1)𝑛 sonli qatorning dastlabki 13 ta hadi yig'indisini hisoblang.
- 0
- 1
- 2
- 1
Javobni ko'rish
1
#133
∑𝑛=1 ∞ (−1)𝑛 sonli qatorning dastlabki 11 ta hadi yig'indisini hisoblang.
- 2
- 1
- 0
- 1
Javobni ko'rish
1
#134
∑𝑛=1 ∞ (−1)𝑛 sonli qatorning dastlabki 12 ta hadi yig'indisini hisoblang.
- 1
- 1
- 0
- 2
Javobni ko'rish
0
#135
1 + 1 5 + 1 25 + 1 125 + ⋯+ 1 5𝑛+ ⋯ ni hisoblang.
- 1
- 5
- 1
- 4
Javobni ko'rish
5
#136
∑𝑛=1 ∞ 3 𝑛(𝑛+1) sonli qatorning yig'indisini toping.
- 2
- 0
- 3
- 3
Javobni ko'rish
3
#137
1 2⋅3 + 1 3⋅4 + 1 4⋅5 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛=
- 𝑎𝑛=
- 𝑎𝑛= 𝑛
- 𝑎𝑛=
Javobni ko'rish
𝑎𝑛=
#138
2 + 5 + 8 + 11 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛= 4𝑛−2
- 𝑎𝑛= 2𝑛+ 1
- 𝑎𝑛= 𝑛+ 1
- 𝑎𝑛= 3𝑛−1
Javobni ko'rish
𝑎𝑛= 3𝑛−1
#139
5 3⋅4 + 5 4⋅5 + 5 5⋅6 + ⋯86 sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛=
- 𝑎𝑛=
- 𝑎𝑛=
- 𝑎𝑛= 𝑛
Javobni ko'rish
𝑎𝑛=
#140
4 + 6 + 8 + 10 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛= 𝑛+ 3
- 𝑎𝑛= 2𝑛+ 2
- 𝑎𝑛= 4𝑛−2
- 𝑎𝑛= 3𝑛+ 1
Javobni ko'rish
𝑎𝑛= 2𝑛+ 2
#141
1 3 + 1 9 + 1 27 + ⋯+ 1 3𝑛+ ⋯ ni hisoblang.
- 1
- 1
- 1
- 1
Javobni ko'rish
1
#142
1 2 + 1 4 + 1 8 + ⋯ ni hisoblang.
- 3
- 2
- 1
- 1
Javobni ko'rish
1
#143
1 4 + 1 16 + 1 64 + ⋯ ni hisoblang.
- 1
- 1
- 1
- 1
Javobni ko'rish
1
#144
1 5 + 1 25 + 1 125 + ⋯+ 1 5𝑛+ ⋯ ni hisoblang.
- 4
- 1
- 1
- 1
Javobni ko'rish
1
#145
1 2 + 1 6 + 1 12 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛=
- 𝑎𝑛= 𝑛
- 𝑎𝑛=
- 𝑎𝑛=
Javobni ko'rish
𝑎𝑛=
#146
5 + 8 + 11 + 14 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛= 2𝑛+ 3
- 𝑎𝑛= 4𝑛+ 1
- 𝑎𝑛= 3𝑛+ 2
- 𝑎𝑛= 6𝑛−1
Javobni ko'rish
𝑎𝑛= 3𝑛+ 2
#147
2 + 3 + ⋯+ 𝑛+ ⋯ sonli qatorning dastlabki 𝑛 ta hadi yig'indisini hisoblang.
- (𝑛+1)(𝑛+2)
- 𝑛
- 𝑛(𝑛+3)
- 𝑛+3
Javobni ko'rish
𝑛(𝑛+3)
#148
∑𝑛=1 ∞ (−1)𝑛+1 sonli qatorning dastlabki 11 ta hadi yig'indisini hisoblang.
- 0
- 1
- 1
- 2
Javobni ko'rish
1
#149
∑𝑛=1 ∞ (−1)𝑛+1 sonli qatorning dastlabki 14 ta hadi yig'indisini hisoblang.
- 2
- 1
- 1
- 0
Javobni ko'rish
0
#150
1 3 + 1 9 + 1 27 + ⋯+ 1 3𝑛+ ⋯ ni hisoblang.
- 1
- 1
- 1
- 2
Javobni ko'rish
1
#151
∑𝑛=1 ∞ 3 𝑛(𝑛+1) sonli qatorning yig'indisini toping.
- 2
- 3
- 1
- 0
Javobni ko'rish
3
#152
1 2⋅3 + 1 3⋅5 + 1 4⋅7 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛=
- 𝑎𝑛=
- 𝑎𝑛=
- 𝑎𝑛= 𝑛
Javobni ko'rish
𝑎𝑛=
#153
1 4 + 1 16 + 1 64 + ⋯ ni hisoblang.
- 1
- 1
- 1
- 1
Javobni ko'rish
1
#154
∑𝑛=1 ∞ (−1)𝑛 4𝑛+1 sonli qatorning beshinchi hadini hisoblang.
- 1
- −
- −
- 1
Javobni ko'rish
−
#155
∑𝑛=1 ∞ 1 𝑛(𝑛+1) sonli qatorning dastlabki 6 ta hadi yig`indisini hisoblang.
- 6
- 1
- 1
- 4
Javobni ko'rish
6
#156
∑𝑛=1 ∞ 1 3𝑛 sonli qator yaqinlashuvchimi?
- ha, yaqinlashuvchi
- to'g'ri javob berilmagan
- yo'q, uzoqlashuvchi
- ham yaqinlashuvchi, ham uzoqlashuvchi
Javobni ko'rish
yo'q, uzoqlashuvchi
#157
4 + 8 + 12 + ⋯+ 4𝑛+ ⋯ sonli qatorning dastlabki 𝑛 ta hadi yig'indisini hisoblang.
- 2𝑛(𝑛+ 1)
- 𝑛
- (𝑛+ 1)(𝑛+ 2)
- 𝑛
Javobni ko'rish
(𝑛+ 1)(𝑛+ 2)
#158
∑𝑛=1 ∞ (−1)𝑛 sonli qatorning dastlabki 5 ta hadi yig'indisini hisoblang.
- 2
- 0
- 1
- 1
Javobni ko'rish
1
#159
∑𝑛=1 ∞ (−1)𝑛 sonli qatorning dastlabki 7 ta hadi yig'indisini hisoblang.
- 1
- 0
- 1
- 2
Javobni ko'rish
0
#160
∑𝑛=1 ∞ 4 𝑛(𝑛+1) sonli qatorning yig'indisini toping.
- 4
- 0
- 4
- 2
Javobni ko'rish
4
#161
4 + 7 + 10 + 13 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛= 4𝑛−2
- 𝑎𝑛= 2𝑛+ 2
- 𝑎𝑛= 𝑛+ 1
- 𝑎𝑛= 3𝑛+ 1
Javobni ko'rish
𝑎𝑛= 3𝑛+ 1
#162
2 3⋅4 + 2 4⋅5 + 2 5⋅6 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛=
- 𝑎𝑛= 𝑛
- 𝑎𝑛=
- 𝑎𝑛=
Javobni ko'rish
𝑎𝑛=
#163
5 + 7 + 9 + 11 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛= 4𝑛−2
- 𝑎𝑛= 3𝑛+ 1
- 𝑎𝑛= 𝑛+ 4
- 𝑎𝑛= 2𝑛+ 3
Javobni ko'rish
𝑎𝑛= 2𝑛+ 3
#164
2 + 1 3 + 1 9 + 1 27 + ⋯+ 1 3𝑛+ ⋯ ni hisoblang.
- 2
- 2
- 2
- 2
Javobni ko'rish
2
#165
2 + 1 2 + 1 4 + 1 8 + ⋯ ni hisoblang.
- 3
- 1
- 2
- 4
Javobni ko'rish
3
#166
1 + 1 4 + 1 16 + 1 64 + ⋯ ni hisoblang.
- 1
- 1
- 1
- 1
Javobni ko'rish
1
#167
1 + 1 5 + 1 25 + 1 125 + ⋯+ 1 5𝑛+ ⋯ ni hisoblang.
- 1
- 1
- 2
- 1
Javobni ko'rish
1
#168
3 + 8 + 13 + 18 + ⋯ sonli qator berilgan. 𝑎𝑛 ni toping.
- 𝑎𝑛= 2𝑛+ 3
- 𝑎𝑛= 5𝑛−2
- 𝑎𝑛= 6𝑛−3
- 𝑎𝑛= 4𝑛−1
Javobni ko'rish
𝑎𝑛= 5𝑛−2
#169
1 2 − 1 4 + 1 8 + ⋯ ni hisoblang.
- 0
- 1
- 1
- 1
Javobni ko'rish
1
#170
1 − 1 4 + 1 16 − 1 64 + ⋯ ni hisoblang.
- 1
- 4
- 1
- 1
Javobni ko'rish
4
#171
1 − 1 5 + 1 25 − 1 125 + ⋯+ (−1)𝑛+1 5𝑛 + ⋯ ni hisoblang.
- 5
- 1
- 1
- 4
Javobni ko'rish
5
#172
𝑦′ = sin 𝑥 tenglamaning yechimini toping.
- sin 𝑥+ 𝐶
- −cos 𝑥+ 𝐶
- −sin 𝑥+ 𝐶
- cos 𝑥+ 𝐶
Javobni ko'rish
−cos 𝑥+ 𝐶
#173
𝑦′ = cos 𝑥 tenglamaning yechimini toping.
- cos 𝑥+ 𝐶
- −sin 𝑥+ 𝐶
- sin 𝑥+ 𝐶
- −cos 𝑥+ 𝐶
Javobni ko'rish
sin 𝑥+ 𝐶
#174
𝑦′ = tan 𝑥 tenglamaning yechimini toping.
- ln |sin 𝑥| + 𝐶
- ln cos 𝑥+ 𝐶
- −ln |cos 𝑥| + 𝐶
- −ln sin 𝑥+ 𝐶
Javobni ko'rish
−ln |cos 𝑥| + 𝐶
#175
𝑥𝑦′ = 1 tenglamaning yechimini toping.
- ln |𝑥| + 𝐶
- ln 𝑥+ 𝐶
- −ln |𝑥| + 𝐶
- −ln 𝑥+ 𝐶
Javobni ko'rish
ln |𝑥| + 𝐶
#176
𝑦′ = 𝑥+ 1 tenglamaning yechimini toping.
- 𝑥2
- 𝑥2
- 𝑥+ 𝐶
- 𝑥2
Javobni ko'rish
𝑥2
#177
𝑦𝑦′ = 𝑥−1 tenglamaning yechimini toping.
- 𝑦2
- 𝑦2
- 𝑦2
- 𝑦2
Javobni ko'rish
𝑦2
#178
(1 + 𝑦2)𝑑𝑥+ (1 + 𝑥2)𝑑𝑦= 0 tenglamaning yechimini toping.
- arctan 𝑥+ arctan 𝑦= 0
- arctan 𝑥−arctan 𝑦= 𝐶
- arctan 𝑥+ arctan 𝑦= 𝐶
- arctan 𝑥−arctan 𝑦= 0
Javobni ko'rish
arctan 𝑥+ arctan 𝑦= 𝐶
#179
(4 + 𝑦2)𝑑𝑥+ (9 + 𝑥2)𝑑𝑦= 0 tenglamaning yechimini toping.
- arctan
- 2arctan
- arctan
- 2arctan
Javobni ko'rish
2arctan
#180
(4 + 𝑦2)𝑑𝑥= (9 + 𝑥2)𝑑𝑦 tenglamaning yechimini toping.
- arctan
- 2arctan
- arctan
- 2arctan
Javobni ko'rish
2arctan
#181
𝑦(1 + 𝑥2)𝑑𝑦= 𝑥(1 + 𝑦2)𝑑𝑥 tenglamaning yechimini toping.
- 𝑦2 = −(1 + 𝑥2) ⋅𝐶
- 1 + 𝑦2 = (1 + 𝑥2) ⋅𝐶
- 𝑦2 = (1 + 𝑥2) ⋅𝐶
- 1 + 𝑦2 = −(1 + 𝑥2) ⋅𝐶
Javobni ko'rish
1 + 𝑦2 = (1 + 𝑥2) ⋅𝐶
#182
(𝑥+ 1)2𝑑𝑦= (𝑦−2)2𝑑𝑥 tenglamaning yechimini toping.
- 1
- −
- 1
- −
Javobni ko'rish
1
#183
(𝑥+ 1)3𝑑𝑦= (𝑦−2)3𝑑𝑥 tenglamaning yechimini toping.
- 1
- −
- 1
- −
Javobni ko'rish
1
#184
Differensial tenglama deb nimaga aytiladi?
- Erkli o'zgaruvchi va noma'lum funksiya hosilalari yoki differensiallarini bog'lovchi
- Noma'lum funksiyani bog‘ lovchi munosabat differensial tenglama deyiladi
- Erkli o'zgaruvchi va noma'lum funksiya bog'lovchi munosabatlar differensial tenglama
- Erkli o'zgaruvchi va noma'lum funksiya va uning hosilalari yoki differensiallarini bog‘lovchi
Javobni ko'rish
Erkli o'zgaruvchi va noma'lum funksiya va uning hosilalari yoki differensiallarini bog‘lovchi
#185
Oddiy differensial tenglama deb nimaga aytiladi?
- Agar noma'lum funksiya beshta erkli o'zgaruvchiga bog'liq bo'lsa, bunday differensial
- Agar noma'lum funksiya uchta erkli o'zgaruvchiga bog ' liq bo'lsa, bunday differensial
- Agar noma'lum funksiya ikkita erkli o'zgaruvchiga bog'liq bo'lsa, bunday differensial tenglama
- Agar noma'lum funksiya bitta erkli o'zgaruvchiga bog'liq bo'lsa, bunday differensial ' bog
Javobni ko'rish
Agar noma'lum funksiya bitta erkli o'zgaruvchiga bog'liq bo'lsa, bunday differensial ' bog
#186
Differensial tenglamaga kirgan hosilalarning eng yuqori tartibi nima deb ataladi?
- Differensial tenglama tartibi
- Differensial tenglama o'lchami
- Differensial tenglama o'lchovi
- Differensial tenglama yechimi
Javobni ko'rish
Differensial tenglama tartibi
#187
Differensial tenglamaning yechimi deb qanday funksiyaga aytiladi?
- Har qanday funksionalga aytiladi
- Har qanday uzluksiz funksiyaga aytiladi
- Har qanday uzilishga ega bo'lgan funksiyaga aytiladi
- Ixtiyoriy differensiallanuvchi funksiyaga aytiladi
Javobni ko'rish
Ixtiyoriy differensiallanuvchi funksiyaga aytiladi
#188
𝑦′′ + 3𝑦′ = 0 tenglamaning tartibini aniqlang.
- 3
- 1
- 2
- 0
Javobni ko'rish
2
#189
𝑦′′ + 3𝑦4 + cosx = 0 tenglamaning tartibini aniqlang.
- 0
- 2
- 3
- 1
Javobni ko'rish
2
#190
𝑦(6) + 𝑦7 −2x = 0 tenglamaning tartibini aniqlang.
- 1
- 2
- 6
- 0
Javobni ko'rish
6
#191
𝑦(4) + 3x𝑦′ = 0 tenglamaning tartibini aniqlang.
- 1
- 0
- 2
- 4
Javobni ko'rish
4
#192
𝑦′′ + 3𝑦(5) −x = 0 tenglamaning tartibini aniqlang.
- 0
- 5
- 1
- 2
Javobni ko'rish
5
#193
2𝑦′′′ + 𝑦′ + 3 = 0 tenglamaning tartibini aniqlang.
- 0
- 2
- 3
- 1
Javobni ko'rish
3
#194
Birinchi tartibli oddiy differensial tenglamani umumiy ko'rinishini aniqlang.
- 𝐹(𝑥, 𝑦, 𝑦′) = 0
- 𝐹(𝑦, 𝑦′) = 0
- 𝐹(𝑥, 𝑦′) = 0
- 𝐹(𝑥, 𝑦, 𝑐) = 0
Javobni ko'rish
𝐹(𝑥, 𝑦, 𝑦′) = 0
#195
Birinchi tartibli differensial tenglamaga qo'yilgan Koshi masalasini aniqlang.
- 𝑦′ = 𝑓(𝑥, 𝑦) va 𝑦|𝑥=𝑥0 = 𝑦0
- 𝑦′ = 𝑓(𝑥, 𝑦) va 𝑦′|𝑥=𝑥0 = 𝑦0
- 𝑦′ = 𝑓(𝑥, 𝑦) va 𝑦′′|𝑥=𝑥0 = 𝑦0
- 𝑦′ = 𝑓(𝑥, 𝑦) va 𝑥|𝑥=𝑥0 = 𝑦0
Javobni ko'rish
𝑦′ = 𝑓(𝑥, 𝑦) va 𝑦|𝑥=𝑥0 = 𝑦0
#196
𝑥𝑑𝑦+ 𝑦𝑑𝑥= 0 tenglamaning tartibini aniqlang.
- 1
- 3
- 2
- 0
Javobni ko'rish
1
#197
𝑦′′ + 𝑦′ + 5𝑦= 0 tenglamaning tartibini aniqlang.
- 0
- 3
- 1
- 2
Javobni ko'rish
2
#198
𝑥√1 −𝑦2𝑑𝑥+ 𝑦√1 −𝑥2𝑑𝑦= 0 tenglamaning tartibini aniqlang.
- 3
- 1
- 0
- 2
Javobni ko'rish
1
#199
O'zgaruvchilari ajraladigan differensial tenglamani ko'rsating.
- 𝑦′ = 𝑃(𝑥, 𝑦)
- 𝑦′ + 𝑃(𝑥)𝑦= 𝑄(𝑦)
- to'g'ri javob keltirilmagan
- 𝑦′ = 𝑓(𝑥)𝑔(𝑦)
Javobni ko'rish
𝑦′ = 𝑓(𝑥)𝑔(𝑦)
#200
𝑦′sin 𝑥−𝑦cos 𝑥= 0 tenglamaning yechimini toping.
- 𝑦= sin 𝑥⋅𝐶
- 𝑦= cos 𝑥⋅𝐶
- 𝑦= −sin 𝑥⋅𝐶
- 𝑦= −cos 𝑥⋅𝐶
Javobni ko'rish
𝑦= sin 𝑥⋅𝐶
#201
𝑦′sin 𝑥+ 𝑦cos 𝑥= 0 tenglamaning yechimini toping.
- 𝑦= cos 𝑥⋅𝐶
- 𝑦⋅cos 𝑥= 𝐶
- 𝑦⋅sin 𝑥= 𝐶
- 𝑦= −sin 𝑥⋅𝐶
Javobni ko'rish
𝑦⋅sin 𝑥= 𝐶
#202
3𝑦′sin 𝑥−𝑦cos 𝑥= 0 tenglamaning yechimini toping.
- 𝑦3 = cos 𝑥⋅𝐶
- 𝑦3 = sin 𝑥⋅𝐶
- 𝑦3 = −sin 𝑥⋅𝐶
- 𝑦3 = −cos 𝑥⋅𝐶
Javobni ko'rish
𝑦3 = sin 𝑥⋅𝐶
#203
𝑦′sin 𝑥−3𝑦cos 𝑥= 0 tenglamaning yechimini toping.
- 𝑦= −cos3 𝑥⋅𝐶
- 𝑦= −sin3 𝑥⋅𝐶
- 𝑦= sin3 𝑥⋅𝐶
- 𝑦= cos3 𝑥⋅𝐶
Javobni ko'rish
𝑦= sin3 𝑥⋅𝐶
#204
𝑦′x −y = 0 tenglamaning yechimini toping.
- 𝑦= 𝑥+ 𝐶
- 𝑦= − 𝑥⋅𝐶
- 𝑦= −x + 𝐶
- 𝑦= 𝑥⋅𝐶
Javobni ko'rish
𝑦= 𝑥⋅𝐶
#205
𝑦′x −y = 0 tenglamaning yechimini toping.
- 𝑦= 𝑥⋅𝐶
- 𝑦= 𝑥+ 𝐶
- 𝑦= − 𝑥⋅𝐶
- 𝑦= −x + 𝐶
Javobni ko'rish
𝑦= 𝑥⋅𝐶
#206
5 ta kitobni kitob javoniga necha xil usulda joylashtirish mumkin?
- 25
- 120
- 100
- 115
Javobni ko'rish
120
#207
4 ta kitobni kitob javoniga necha xil usulda joylashtirish mumkin?
- 16
- 24
- 15
- 25
Javobni ko'rish
24
#208
3 ta kitobni kitob javoniga necha xil usulda joylashtirish mumkin?
- 6
- 5
- 10
- 3
Javobni ko'rish
6
#209
1,2 va 3 raqamlaridan nechata uch xonali son yasash mumkin(raqamlar takrorlanmasin)
- 10
- 3
- 5
- 6
Javobni ko'rish
6
#210
5,4 va 3 raqamlaridan nechata uch xonali son yasash mumkin(raqamlar takrorlanmasin)
- 5
- 10
- 3
- 6
Javobni ko'rish
6
#211
1,4 va 6 raqamlaridan nechata uch xonali son yasash mumkin(raqamlar takrorlanmasin)
- 10
- 5
- 3
- 6
Javobni ko'rish
6
#212
1,2 va 3 raqamlaridan nechata uch xonali son yasash mumkin(raqamlar takrorlanishi mumkin)
- 10
- 6
- 27
- 18
Javobni ko'rish
27
#213
0,2 va 3 raqamlaridan nechata uch xonali son yasash mumkin(raqamlar takrorlanmasin)
- 4
- 6
- 5
- 3
Javobni ko'rish
4
#214
0,4 va 5 raqamlaridan nechata uch xonali son yasash mumkin(raqamlar takrorlanmasin)
- 6
- 3
- 5
- 4
Javobni ko'rish
4
#215
Ikkita tanga tashlanganda kamida bitta raqam tomon tushish ehtimolini toping?
- 3
- 5
- 1
- 1
Javobni ko'rish
3
#216
Ikkita tanga tashlanganda kamida bitta gerb tomon tushish ehtimolini toping?
- 1
- 1
- 3
- 5
Javobni ko'rish
3
#217
Ikkita tanga tashlanganda faqat bitta raqam tomon tushish ehtimolini toping?
- 3
- 1
- 5
- 1
Javobni ko'rish
1
#218
Ikkita tanga tashlanganda faqat bitta gerb tomon tushish ehtimolini toping?
- 3
- 1
- 1
- 1
Javobni ko'rish
1
#219
Ikkita tanga tashlanganda faqat gerb tomon tushish ehtimolini toping?
- 1
- 1
- 1
- 3
Javobni ko'rish
1
#220
Ikkita tanga tashlanganda faqat gerb tomon tushish ehtimolini toping?
- 1
- 1
- 3
- 1
Javobni ko'rish
1
#221
Muqarrar hodisaning ehtimoli nimaga teng?
- 1
- 1
- 1
- 0
Javobni ko'rish
1
#222
Mumkin bo’lmagan hodisaning ehtimoli nimaga teng?
- 0
- 1
- 1
- 1
Javobni ko'rish
0
#223
O’yin kubigi bir marta tashlanganda 2 raqam chiqish ehtimolini toping?
- 1
- 3
- 1
- 1
Javobni ko'rish
1
#224
O’yin kubigi bir marta tashlanganda 3 raqam chiqish ehtimolini toping?
- 3
- 1
- 1
- 1
Javobni ko'rish
1
#225
O’yin kubigi bir marta tashlanganda 6 raqam chiqish ehtimolini toping?
- 3
- 1
- 1
- 1
Javobni ko'rish
1
#226
O’yin kubigi bir marta tashlanganda juft son chiqish ehtimolini toping?
- 3
- 1
- 1
- 1
Javobni ko'rish
1
#227
O’yin kubigi bir marta tashlanganda toq son chiqish ehtimolini toping?
- 1
- 1
- 1
- 3
Javobni ko'rish
1
#228
O’yin kubigi bir marta tashlanganda 2 ga karrali son chiqish ehtimolini toping?
- 3
- 1
- 1
- 1
Javobni ko'rish
1
#229
O’yin kubigi bir marta tashlanganda 3 ga karrali son chiqish ehtimolini toping?
- 1
- 1
- 1
- 3
Javobni ko'rish
1
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